Don't raise on failed smoke test exit code

Because we don't catch the exception and then the whole script bails out
so we don't end up printing the error log from the process.

Keep raising on --debug just to maintain the behaviour, eg fail the
build if the process fails.
I'm not sure we actually want this behaviour though. As it is we won't
get the output printed out on failed debug builds. So maybe we
shouldn't be skipping the output check? I don't quite get what the
intention is here.

1 files changed, 14 insertions, 16 deletions

diff --git a/scripts/dev/build_release.py b/scripts/dev/build_release.py
index 953a2a1be..50f27720a 100755
--- a/scripts/dev/build_release.py
+++ b/scripts/dev/build_release.py
@@ -110,6 +110,7 @@ def _filter_whitelisted(output: bytes, patterns: Iterable[str]) -> Iterable[str]
 def _smoke_test_run(
     executable: pathlib.Path,
     *args: str,
+    capture_output: bool=True
 ) -> subprocess.CompletedProcess:
     """Get a subprocess to run a smoke test."""
     argv = [
@@ -121,7 +122,7 @@ def _smoke_test_run(
         'about:blank',
         ':cmd-later 500 quit',
     ]
-    return subprocess.run(argv, capture_output=True)
+    return subprocess.run(argv, check=False, capture_output=capture_output)
 
 
 def smoke_test(executable: pathlib.Path, debug: bool, qt5: bool) -> None:
@@ -181,25 +182,22 @@ def smoke_test(executable: pathlib.Path, debug: bool, qt5: bool) -> None:
             r'module could not be found. \(0x7E\)'),
         ])
 
-    proc = _smoke_test_run(executable)
+    proc = _smoke_test_run(executable, capture_output=not debug)
+    if debug:
+        print("Skipping output check for debug build")
+        proc.check_returncode()
+        return
 
     stdout = '\n'.join(_filter_whitelisted(proc.stdout, stdout_whitelist))
     stderr = '\n'.join(_filter_whitelisted(proc.stderr, stderr_whitelist))
 
-    if stdout or stderr or proc.returncode > 0:
-        if debug:
-            print(
-                f"Unexpected output (errno={proc.returncode})"
-            )
-            debug_stdout = None
-            debug_stderr = None
-        else:
-            print(
-                f"Unexpected output, running with --debug (errno={proc.returncode})"
-            )
-            proc = _smoke_test_run(executable, '--debug')
-            debug_stdout = proc.stdout.decode('utf-8')
-            debug_stderr = proc.stderr.decode('utf-8')
+    if stdout or stderr or proc.returncode != 0:
+        print(
+            f"Unexpected output, running with --debug (returncode={proc.returncode})"
+        )
+        proc = _smoke_test_run(executable, '--debug')
+        debug_stdout = proc.stdout.decode('utf-8')
+        debug_stderr = proc.stderr.decode('utf-8')
 
         lines = [
             "Unexpected output!",